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Example 1: Evaluate
.
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Substituting 0 for x, you find that cos xapproaches 1 and sin x − 3 approaches −3; hence,
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Example 2: Evaluate 
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Because cot x = cos x/sin x, you find
The numerator approaches 1 and the denominator approaches 0 through positive values because we are approaching 0 in the first quadrant; hence, the function increases without bound and
and the function has a vertical asymptote at x = 0.
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Example 3: Evaluate 
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Multiplying the numerator and the denominator by 4 produces
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Example 4: Evaluate
.
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Because sec x = 1/cos x, you find that
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